Day 8 🧭行动：学习了新的数据容器集合（set） 🤓体会：这里的集合就和数学中的集合很像了。集合是可变无序，元素唯一，不可哈希元素不能存储 🧑‍💻代码： #集合的定义 # si = {1,2,3,44,35,34,65,44} # print(si) #输出结果的顺序随机 # print(type(si)) # so = set() # print(so, type(so)) # s1 = {11,21,23,43,45,56,76,78,98} # #添加指定元素 # s1.add(10) # print(s1) # #删除指定元素 # s1.remove(11) # print(s1) # #删除随机元素并返回 # e = s1.pop() # print(e) # print(s1) # #删除集合 # s1.clear() # print(s1) # # s2 = {"A","D","A","W","H","F","I"} # s3 = {"F","J","T","S","W"} # #输出差集，前者有后者没有的集合 # print(s2.difference(s3)) # print(s3.difference(s2)) # #输出两个集合的并集 # print(s2.union(s3)) # print(s3.union(s2)) # #输出两个集合的交集 # print(s2.intersection(s3)) # print(s3.intersection(s2)) #选修足球的学生名单 football_set = {"王林", "曾牛", "徐立国", "遁天", "天运子", "韩立", "厉飞雨","乌丑","紫灵"} #选修篮球的学生名单 basketball_set = {"张铁", "墨居仁","王林", "姜老道", "曾牛", "王蝉", "韩立", "天运子", "李化元", "厉飞雨", "云露"} # 选修法语学生名单 french_set = {"许木", "王卓", "十三", "虎咆", "姜老道", "天运子", "红蝶", "厉飞雨", "韩立", "曾牛"} # 选修艺术学生名单 art_set = { "遁天", "天运子", "韩立", "虎咆", "姜老道", "紫灵"} #方法一 # fa_set = french_set.intersection(art_set) # print("同时选修法语和艺术的学生：",fa_set) #方式二，&替代 fa_set = french_set & art_set print("同时选修法语和艺术的学生：",fa_set) all_set = football_set & basketball_set & french_set & art_set print("同时选修四门课程的学生：",all_set) #方法一 # fb_set = football_set.difference(basketball_set) # print("选修足球且没有选修篮球的学生：",fb_set) #方法二：“-” 用来求差集 # fb_set = football_set - basketball_set # print("选修足球且没有选修篮球的学生：",fb_set) #方法三：集合表达式 fb_set = {s for s in football_set if s not in basketball_set} print("选修足球且没有选修篮球的学生：",fb_set) #并集：“|” all_set2 = football_set | basketball_set | french_set | art_set all_list =[*football_set,*basketball_set,*french_set,*art_set,*fa_set] for i in all_list: print(f"{i} 选修了 {all_list.count(i)} 门课")